LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
1.2k views
in Physics by (21.2k points)
edited by

A 100 μF capacitor is in series with a 40Ω  resistor and is connected to a 100 V, 50 Hz AC source. Calculate the following 

(a) Maximum current in the circuit. 

(b) Time lag between current maximum and voltage maximum.

1 Answer

+1 vote
by (72.5k points)
selected by
 
Best answer

Given , Vrms = 100 V , C = 100F = 100 x 106 F , R = 40 Ω

Total impedance of the circuit

(b) For pure capacitor, phase difference ϕ = p/2

Time difference = T/2Phase difference 

Time lag between current maximum and voltage maximum = 1/200s.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...