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A mass m attached to a horizontal mass less spring with spring constant k, is set into simple harmonic motion. Its maximum displacement from its equilibrium position is A. What is the masses speed as it passes through its equilibrium position?

(A) 0

(B) A√(k/m)

(C) A√(m/k)

(D) 1/A√(k/m)

(E) 1/A√(m/k)

1 Answer

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Best answer

Correct option (B) A√(k/m)

Conservation of Energy, Usp = K, ½ kA2 = ½ mv2 solve for v

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