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A ball is thrown vertically upwards with a velocity v and an initial kinetic energy Ek. When half way to the top of its flight, it has a velocity and kinetic energy respectively of

(A) v/2, Ek/2

(B) v/√2, Ek/2

(C) v/4, Ek/2

(D) v/2, Ek/√2

(E) v/√2, Ek/√ 2

1 Answer

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Best answer

Correct option (B) v/√2, Ek/2   

Half way up you have gained half of the height so you gained ½ of potential energy. 

Therefore you must have lost ½ of the initial kinetic energy 

so E2 = (Ek/2).

Subbing into this relationship E2 = (Ek/2) 

½ mv22 = ½ mv2/ 2

v22 = v2/2 …. Sqrt both sides gives answer

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