Question

An ideal spring obeys Hooke's law, F = -kx. A mass of 0.50 kilogram hung vertically from this spring stretches the spring 0.075 meter. The value of the force constant for the spring is most nearly 

(A) 0.33 N/m

(B) 0.66 N/m

(C) 6.6 N/m 

(D) 33 N/m 

(E) 66 N/m

Answer 1

Correct option (E) 66 N/m

Force is provided by the weight of the mass (mg). Simply plug into F = k∆x, mg = k∆x and solve.