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Explain the oxidizing property of K2Cr2O7.

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Explain the oxidizing property of K2Cr2O7.

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K2Cr2O7 acts as an oxidizing agent. In acid medium it undergoes reduction to Cr3+ 

Cr2O72- + 14H++ 6e- → 2Cr3+(green) + 7H2O 

Eg: acidified K2Cr2O7 will oxidize 

(a) Fe2+ to F3+ 

Cr2O72- + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O 

(b) Iodide to iodine 

Cr2O72- + 6I- + 14H+ → 3I2 + 2Cr3+ + 7H2O

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