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One mole of nitrogen is mixed with 3 moles of hydrogen in 4-litre container. If 0.50 % of nitrogen is converted to ammonia by the following reaction,

N2(g) + 3H2(g) ⇋ 2NH3(g),

Calculate the equilibrium constant (Kc) in concentration units. What will be the value of Kc for the following equilibrium? 

1/2N2(g) + 3/2H2(g) ⇋ 2NH3(g),

1 Answer

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Best answer

Using the reaction, calculate equilibrium concentration and Kc . Apply the formula for the next reaction and solve the new Kc.

We can see that the above reaction has been obtained by multiplying the equation

N2(g) + 3H2(g) ⇋ 2NH3(g), by 1/2.

Thus, the new equilibrium constant = (6.0 × 10–5)1/2 Kc = 7.7 x 10-3(mole/litre)–1

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