Question

Find the Interplanar spacing for a (1 2 1) plane in a simple cubic lattice whose lattice constant is 0.412 nm. 

(a)  0.01 nm (b) 0.11 nm (c) 0.14 nm (d) 0.16 nm  

Answer 1

Correct option (d) 0.16 nm

Explanation:

For a cubic lattice the interplanar distance is d = a/√(h² + l² + k²)

where, d = Interplanar distance

a = lattice parameter

(hkl) is the Miller indices of the plane