For the Balmer transition, n = 4, to n = 2 in a He+ ion, we can write.
Equating equation (ii) and (i), we get
This equation gives n1 = 1 and n = 2. Thus the transition n = 2 to n = 1 in hydrogen
atom will have same wavelength as transition, n = 4 to n = 2 in He+