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Find the ratio of the number of atoms present in 16g of O2 and 32g of O3

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Number of atom = moles x Avogadro's number x atomicity   

Moles of O2 = 16/32 = 1/2 

Moles of O3 = 32/48 =2/3  

No. of atom of O2/ No. of atom of O3 

=( 1/2 x Na x 2)/(2/3 x Na x 3)  

Ratio will be=1:2

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