Find the ratio of the number of atoms present in 16g of O2 and 32g of O3

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rubby · Answer 1 · 2019-05-31T21:58:33+0000

Number of atom = moles x Avogadro's number x atomicity

Moles of O₂ = 16/32 = 1/2

Moles of O₃ = 32/48 =2/3

No. of atom of O₂/ No. of atom of O₃

=( 1/2 x Na x 2)/(2/3 x Na x 3)

Ratio will be=1:2