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A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground ? [g = 10 m/s2 , sin30° = 1/2, cos30° = √3/ 2 ]

(a) 5.20 m 

(b) 4.33 m

(c) 2.60 m 

(d) 8.66 m.

1 Answer

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(d) : Height of building = 10 m The ball projected from the roof of building will be back to roof height of 10 m after covering the maximum horizontal range. Maximum horizontal range.


 

by (10 points)
Can u show the diagram please.

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