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Arrange the following compounds in the increasing order of homolytic (C – C) bond dissociation energy.

I. Propane

II. Ethane

III. 2, 2–Dimethyl propane

IV. 2–Methyl propane

(A)  (III) < (IV) < (II) < (I)

(B)  (II) < (I) < (IV) < (III)

(C)  (III) < (IV) < (I) < (II)

(D)  (I) < (III) < (II) < (IV)

1 Answer

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Best answer

Correct option (C) (III) < (IV) < (I) < (II)

Explanation:

Making and breaking of bonds is the basis of all chemical transformation. Bond dissociation energy is the measure of the strength of a chemical bond. According to the experimental bond enthalpies the order is III < IV <I < II.

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