If a & b are the zeros of the polynomial x^{2} - x - 6.

X^{2} - (a+b)x + ab

So, x^{2} - x - 6 = x^{2} - (a+b)x + ab

On comparing, we get:

a + b = 1 ......(i) and

ab = -6 ........(ii)

The polynomial whose zeroes are (3a+2b) & (2a+3b) will be written as:

x^{2} - [(3a+2b) + (2a+3b)]x + [(3a+2b) x (2a+3b)]

= x^{2} - [3a+2b+2a+3b]x + 0 [from (iii)]

= x^{2} - [5a+5b]x + 0

= x^{2} - (5 x 1)x

= x^{2} - 5x