Question

1 atom of an element weighs 1.792 × 10²² g. The Atomic mass of the element is 

(A) 108 

(B) 17.92 

(C) 1.192 

(D) 64 

Answer 1

Correct option is (1) 108

We know,

According to Avogadro's law, 1 mole of every substance weighs equal to the atomic mass and contains Avogadro's number 6.023 × 10²³ of particles.

Given,

One atom of an element weights 1.792 × 10^-22 g

Thus, 1 atom weights = 1.792 × 10^-22 g

6.023 × 10²³ atoms will weight = 1.792 × 10^-22 × 6.023 × 10²³

= 1.792 × 6.023 × 10

 = 108

Answer 2

1 atom of an element weighs 1.792 × 10²² g. The Atomic mass of the element is  108.

Explanation :-

Atomic weight of the element = 1.792 × 10⁻²² × 6.022 × 10²³ = 108