Question

A light ray enters a rectangular glass slab at an incident angle of 60 degrees. The glass slab has an with index of refraction n = 1.6 and a thickness T. The beam emerging from the other side of the glass slab is parallel to the incident beam but displaced by a distance d as shown in the Figure. What is the displacement d?

Answer 1

From Snell’s Law we know that n₁sin θ₁ = n₀ sin θ₀ and solving for θ₁ gives

Now if we let x be the distance the light ray travels within the glass we see that