Question

The voltage of an ac source varies with time according to the equation V = 100 sin(100πt) cos(100πt) where t is in seconds and V is in volts. Then 

(a) The peak voltage of the source is 100 volts 

(b) The peak voltage of the source is 50 volts 

(c) The peak voltage of the source is 100 / √2 volts 

(d) The frequency of the source is 50 Hz

Answer 1

The correct option is (b) The peak voltage of the source is 50 volts.

Explanation:

The given equation can be written as follows