Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
12 views
asked ago in Chemistry by (32.5k points)

A gas ‘X’ is passed through water to form a saturated solution. The aqueous solution on treatment with silver nitrate gives a white ppt.. The saturated aqueous solution also dissolve magnesium ribbon with the evolution of a colourless gas ‘Y’. Identify ‘X’ and ‘Y’.

(A) X=CO2, Y=Cl

(B) X=Cl2, Y=CO

(C) X=Cl2, Y=H

(D) X2 =H2, Y=Cl2

1 Answer

+1 vote
answered ago by (66.8k points)
selected ago by
 
Best answer

Correct Option (C) X=Cl2 , Y=H2

Explanation:

X + H2O → Saturated solution

X(ag) + AgNO3 → White ppt. AgCl

X(ag) + Mg → Colourless gas MgCl2

X = Cl2 ; Y = H2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Categories

...