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+1 vote
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in Physics by (68.8k points)

A light rod of length 200 cm is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of crosssectional area 0.1 cm2 and the other is of brass of crosssectional area 0.2 cm2 . Find out the position along the rod at which weights may be hung to produce 

(a) equal stress in both wires 

(b) equal strains in both wires. Ysteel = 20 x 1011 dynes/cm2 and YBrass = 10 x 1011 dynes/cm2 .

1 Answer

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by (72.0k points)
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Best answer

(a) Let a weight W be suspended from a point C on the rod such that it is x cm from the steel wire. Let the forces in steel & brass wires be F1 and F2 respectively. 

(b) Let the weight w be hung at a point y cm away from the steel wire and forces developed in the steel & brass wires be F3 and F4 respectively

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