Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
16.4k views
in Physics by (61.3k points)

The first overtone frequency of a closed organ pipe p1 is equal to the fundamental frequency of an open organ pipe p2 . If the length of the pipe p1 is 30cm. What will be the length of p2 ?

(A) 12 cm (B) 24 cm (C) 20 cm (D) 38 cm

1 Answer

+2 votes
by (64.1k points)
selected by
 
Best answer

Correct option (C) 20 cm

Explanation :

According to the questions f1 first overtone of a closed organ pipe

P1 = 3v/4I = 3 x V/4 x 30

f2 fundamental frequency of a open organ pipe P2 = V/2I2

Here given 3V/4 x 30 = V/2I2

I2 = 20 cm

 Length of the pipe P2 will be 20 cm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...