Question

A simple pendulum with angular frequency ω oscillates simple harmonically. The tension in the string at lowest point is T. The total acceleration of the bob at its lowest position is 

(A) (T/m – g) 

(B) Zero 

(C) g – T/m 

(D) T + g/m

Answer 1

Correct Option :- (A) (T/m – g)

Explanation :-

At the lowest point, the tangential acceleration = 0, but since the bob is moving in a circle, it will have centripetal acceleration.