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Find all the zeroes of the polynomial x3 - 6x2 +11x - 6 if two of its zeroes are 1 and 2.

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Let f(x) = x3 - 6x2 + 11x - 6 

Given: (x-1)(x-2) are the zeros of f(x). 

product of zeros = (x-1)(x-2) = x2 - 2x - x + 2 = x2 -3x + 2 

therefore, on dividing the f(x) with x2 - 3x + 2 , we get, x-3 

Now, x - 3 = 0 

x = 3

Hence, the other zero is 3.

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