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asked in Mathematics by (32.2k points)

find focal distance of point P on the parabola 5y2 = 12x if the abscissa of P is equal to 7 

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answered by (27.6k points)
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Best answer

STEP 1 : 

Equation of parabola : 

5y2 = 12x 

 y2 = 12x/5 

On comparing with : 

y2 = 4ax , 

4a = 12/5 , 

a = 3 /5  

STEP 2 : 

Focal distance of point P(7,y) 

= PS 

= PM ……….. FOCUS DIRECTRIX PROPERTY 

= x + a = 7 + 3/5 

= 38/5 units 

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