STEP 1 :
Equation of parabola : y2 = 32x
On comparing with : y2 = 4ax , 4a = 32 , a = 8
STEP 2 :
Focal distance of point P(x,y) = 10
PS = 10
PM = 10 ……….. FOCUS DIRECTRIX PROPERTY
x + a = 10
x + 8 = 10
x = 2
STEP 3 :
P(2 , y) lies on parabola y2 = 32x & hence it must satisfy the equation of parabola
∴ y2 = 16(2)
y2 = 64 ,
y = ± 8
∴ P(2,8) & P’(2,–8)