STEP 1 :

Equation of parabola : y^{2} = 32x

On comparing with : y^{2} = 4ax , 4a = 32 , a = 8

STEP 2 :

Focal distance of point P(x,y) = 10

PS = 10

PM = 10 ……….. FOCUS DIRECTRIX PROPERTY

x + a = 10

x + 8 = 10

x = 2

STEP 3 :

P(2 , y) lies on parabola y^{2} = 32x & hence it must satisfy the equation of parabola

∴ y^{2} = 16(2)

y^{2} = 64 ,

y = *±* 8

*∴* P(2,8) & P’(2,–8)