STEP 1 :
Equation of parabola : y2 = 4x
On comparing with : y2 = 4ax , 4a = 4 , a = 1
STEP 2 :
Focal distance of point P(x,y) = 5
PS = 5
PM = 5 ……….. FOCUS DIRECTRIX PROPERTY
x + a = 5
x + 1 = 5
x = 4
STEP 3 :
P(4 , y) lies on parabola y2 = 4x & hence it must satisfy the equation of parabola
∴ y2 = 4(4)
y2 = 16 , `
y = ± 4
∴ P(4,4) & P’(4,-4)