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Two masses of 5 kg and 3 kg are suspended with help of mass less in extensible string as shown. Calculate T1 and T2 when system is going upwards with acceleration m/s2. (Use g = 9.8 m/s2

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According Newton’s second law of motion

(i) T1 – (m1 + m2)g = (m1 + m2)a 

T1 = (m1 + m2)(a + g) 

= (5 + 3) (2 + 9·8) 

 T1 = 94·4 N 

(ii) T2 – m2g = m2

T2 = m2(a + g) 

T2 = 3(2 + 9·8) 

T2 = 35·4 N

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