Question

Two masses of 5 kg and 3 kg are suspended with help of mass less in extensible string as shown. Calculate T₁ and T₂ when system is going upwards with acceleration m/s². (Use g = 9.8 m/s²) 

Answer 1

According Newton’s second law of motion

(i) T₁ – (m₁ + m₂)g = (m₁ + m₂)a 

T₁ = (m₁ + m₂)(a + g) 

= (5 + 3) (2 + 9·8) 

 T₁ = 94·4 N 

(ii) T₂ – m₂g = m₂a 

T₂ = m₂(a + g) 

T₂ = 3(2 + 9·8) 

T₂ = 35·4 N