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The sum 50Σn=1 tan-1(2n/n4-n2+1) equals tan^–1K, where K equal

(A) 5050 

(B) 2550 

(C) 4950 

(D) 2525

1 Answer

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Best answer

Tn = tan–1n(n + 1) – tan–1 n(n – 1) 

Sn = tan–1n(n + 1) 

S50 = tan–1 (2550)

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