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If ⊕ is a binary operation on R defined by a ⊕ b = a / 4 + b / 7 for a, b ⊕ R, then show that : (2 ⊕ 5) ⊕ 7  2 ⊕ (5 ⊕ 7).

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(2 ⊕ 5) ⊕ 7 = 73/ 56 

⇒ 2 ⊕ (5 ⊕ 7) = 23 / 28

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