# The vertical height of the projectile at time t is given by y = 4t – 5t^2 and the horizontal distance covered is given by x = 3t.

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The vertical height of the projectile at time t is given by y = 4t – 5t2 and the horizontal distance covered is given by x = 3t. What is the angle of projection with the horizontal?

(A) tan–1 3/5

(B) tan–1 4/5

(C) tan–1 4/3

(D) tan–1 3/4

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Correct option (C) tan–1 4/3

Explanation: