A particle is projected at point ‘A’ with initial velocity 5 m/s at an angle θ = 37° with the vertical y axis. A strong horizontal wind gives the particle a constant horizontal acceleration 6m/s2 in the x direction. If the particle strikes the ground at a ground directly under its released position, determine the height ‘h’ of point A. The downward y acceleration is taken as the constant g = 10 m/s2, take (sin37° = 3/5, cos37° = 4/5)
