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Greatest value of y for which equation x2 + 2xy + y2 + y – 1 = 0 (x, y ∈ R) can be solved is ‘α’, then α may be

(A) –1 

(B) 0 

(C) 1 

(D) 2

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Correct Option:- (C) 1

Explanation :-

D ≥0 

(4y2 ) – 4(y2 + y –1) ≥ 0 

⇒ 4y ≤ 4 

⇒ y ≤ 1

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