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A coin is released inside a lift at a height of 2m from the floor of the lift. The height of the lift is 10m. The lift is moving with an acceleration of 9 m/s2 downwards. The time after which the coin will strike with the lift is : (g = 10 m/s2)

(A) 4s 

(B) 2s

(C) 4/√21s

(D) 2/√11s

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Best answer

Correct option (B) 2s

Explanation:

Relative to lift initial velocity and acceleration of coin are 0 m/s and 1 m/s2 downward

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