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If f'(x) = √(2x -1) and y = f(x^2 ), then dy/dx at x = 1 is equal to

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If f'(x) = √(2x -1) and y = f(x2 ), then dy/dx at x = 1 is equal to

(A) 2 

(B) 1 

(C) – 2 

(D) –1

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f'(x) =  √(2x2 -1) , y = f(x2 )

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