Question

Parallel plate capacitors C₁ & C₂ have the same area with C₁ having half the plate separation as C₂ . C₁ is inserted wholly inside C₂ as shown with their plates joined as shown. The capacitance across terminals AB will be

(a)  C₁ + nC₂  

(B)  C₁C₂/C₁ + C2

(c)  C₁ 

(d)  C₂

Answer 1

Correct option  (c) C₁

Explanation:

Since the plates are joined.

Potential of A is equal to potential of C and potential of B is equal to potential of D.

Hence potential difference between AB is equal to potential difference between CD.

∴ Capacitance across AB is equal to capacitance across CD which is C₁ .