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asked in JEE by (20 points)
95g of metal chloride (MCl2) contain 71g of chlorine. The equivalent weight of metal chloride is

2 Answers

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answered by (61.6k points)

Weight of metallic chloride = 95g

weight of chlorine = 71g

Therefore, Weight of metal = 95-71=24

Equivalent weight of metal = weight of metal / weight of chlorine x 71

= 24/71 x 71 = 24

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answered by (328 points)
Moles of chlorine = 71 / 71 = 1,

So, moles of metallic chloride = 1,

Therefore, molar mass of M = 95 - 71 = 24 g

So, clearly the metal is Mg.

Here, n-factor = 2

Hence, EqWt (MCl2) = 95 / 2 = 47.5 g

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