Join Sarthaks eConnect Today - Largest Online Education Community!
+2 votes
asked in JEE by (25 points)

The motion of a body is given by the equation dv/dt=6.0-3v, where v is speed in m/s and t is in second. If body was at rest at t=0, then

1 Answer

+2 votes
answered by (2k points)

Only option (d) is correct ie. the speed is 1.0 m/s when the acceleration is half the initial value.



(B) The terminal speed is the constant speed when acceleration is zero. Thus 

0 = 6.0-3v

v = 2 m/s

(C) At t=0, v=0; therefore initial acceleration a = 6.0-0 = 6.0 m/s2

(D) Acceleration is half that of initial value = 6.0/2 = 3.0m/s2

This gives 3 = 6-3v(t)

or v(t) = 1m/s

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon