what electronic transition in the He+ ion would emit the radiation of the same wavelength as that of the first line in laymen series of hydrogen

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Shradha · Answer 1 · 2019-06-24T05:27:43+0000

For H

1/¥ = R ×1 ( 1/1² - 1/2² )

For He+

I/¥ = R × 2² ( 1/n1 - 1/n2)

According to question ,

They have same wavelength , so equate it

Get final answer n1 =2 , n2 = 4