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0 votes
7.3k views
in Physics by (76.1k points)

According to the fuse law, the current carrying capacity varies as 

(A) diameter 

(B) (diameter)3/2 

(C) 1 / diameter 

(D)1 / (diameter)2 .

1 Answer

+1 vote
by (79.9k points)
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Best answer

(B) (diameter)3/2 

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