Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.1k views
in Mathematics by (115 points)

Please log in or register to answer this question.

1 Answer

0 votes
by (1.3k points)

Let the rth term contain x​​​​9 . In the expansion of (2x - 4)9 , rth term is given by

Tr = 9Cr-1 . (-1)r-1 . (2x)9-r+1 . 4r-1

      9​​​​​Cr-1 . (-1)r-1 . 210-r . (22)r-1 . x10-r

     = 9Cr-1 . (-1)r-1 . 28-r . x​​​​​​10-r             .... (1)

Since the rth term contains x9 , therefore 

10 - r = 9

r = 1 .

From (1), we have

T1 = 9C0 . (-1)0 . 27 . x9

      = 128 x9

So, coefficient of x9 = 128 .

Hence, 128 is the coefficient of xin the given expansion.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...