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If ∑(r^2 + 2r + 1). r! for r ∈ [1, N] = (2014)! –2, then N can be (A) 2012

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If ∑(r2 + 2r + 1). r! for r ∈ [1, N] = (2014)! –2, then N can be

(A) 2012 

(B) 2013 

(C) 2011 

(D) 2014

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Correct option (A) 2012

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