Correct option (b) 4 cal K-1 mol-1
Explanation:
As the gas absorbs heat without change in volume, W = 0 (since, ΔV = 0)
Heat absorbed, q = 60 cal, Since ΔE = q + W
= 60 + 0 = 60 cal; Cv = ΔE/(T2 – T1 ) = 60/(303 – 300) = 20 cal K–1
Since moles of N2 gas given
= 140/28 = 5,
Molar heat capacity
= 20/5 cal K–1 = 4 cal K–1 mol–1