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0 votes
16.6k views
in Chemistry by (284 points)
edited by

19 gram of a mixture containing NaHCO3 and Na2CO3 on complete heating liberated 1.12 litre of CO2 at STP. The weight of the remaining solid was 15.9 gram. What is the weight (in a gram) of Na2CO3 in the mixture before Heating? 

a) 8.4 

b) 15.9 

c) 4.0 

d) 10.6

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1 Answer

+2 votes
by (10.9k points)
Option (d) is correct

The component NaHCO3 can only produce CO2 on heating of the given mixture as per following balanced equation

2NaHCO3-> Na2CO3+H2O+ CO2

This equation reveals that 22.4 L CO2 is produced from 2 moles or 2(23+1+12+3*16)=168g NaHCO3

So 1.12L of CO2 can be obtained from 168/22.4x1.12=8.4g of NaHCO3

So the wt of Na2CO3 in the mixture of 19g before heating was = 19-8.4=10.6g

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