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Let (1 – x – 2x^2)^6 = 1+ a1x + a2x^2 + …. + a12x^12. Then a2/2^2 + a4/2^4 + a6/2^6 + ..... + a12/212 is equal to

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Let (1 – x – 2x2)6 = 1+ a1x + a2x2 + …. + a12x12. Then a2/22 + a4/24 + a6/26 + ..... + a12/212 is equal to

(a)  –1

(b)  –1/2

(c)  0

(d)  1/2 

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Best answer

Correct option  (b) –1/2 

Explanation:

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