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in Mathematics by (71.5k points)

If 'a' is a natural number and 'b' a digit such that (3a + 2007)2 = 4b85924, then

(A) a – b = 31 

(B) a + b = 37 

(C) a + b = 41 

(D) a – b = 33

1 Answer

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Best answer

Correct option (C) (D)

Explanation:

(3a + 2007)2 = 4b85924 

4b85924 must be divisible by 9 

 b = 4

9(a + 669)2 = 4485924 

 (a + 669)2 = 498436

 (a + 669)2 = (706)2

a = 37

 a – b = 33

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