To safely cross the ditch the motorbike should have a minimum range =11.7 ft + 5 ft =16.7 ft.
Let the speed of the motorbike for this range be u. θ =15°,
Range x=(u² sin 2θ )/g
=> 16.7 = (u² sin 30°)/32
=> u² = 16.7*32*2
=> u =√1068.8 = 32.7 ft/s , is the minimum speed required to cross the ditch.