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in Physics by (70.8k points)

The length of a wire between the two ends of a sonometer is 105 cm. Where should the two bridges be placed so that the fundamental frequencies of the three segments are in the ratio of 1 : 3 : 15 ?

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Total length of the wire, L = 105 cm

v1 : v2 : v3 = 1 : 3 : 15

Let L1, L2 and L3 be the length of the three parts. As v ∞ 1/L

Hence the bridges should be placed at 75 cm and (75 + 25) = 100 cm from one end.

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