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in Physics by (79.8k points)

A transverse sinusoidal wave of amplitude a, wavelength λ and frequency f is travelling on a stretched string. The maximum speed of any point on the string is V/10, where V is the speed of propagation of the wave. If a = 10–3 m and V = 10 ms–1, then λ and f are given by 

(a) λ = 2π × 10–2

(b) λ = 10–3

(c) f = 103/2π Hz 

(d) f = 104 Hz.

1 Answer

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Best answer

Let y = a sin (kx – ωt)

Then y = – aω cos (kx – ωt)

Maximum speed of a point on the string = aω.

Correct Choice : a, c

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