Annual salary received by Suba Rao in 1995, 1996, 1997, . . . . is
Rs 5000, 5200, 5400, . . . .
Clearly, it is arithmetic progression with first term a = 5000 and commond difference d = 2000
Suppose Suba Rao's annual salary reaches to Rs 7000 in nth year. Then n th term of the above A.P. = Rs. 7000
⇒ a + (n – 1)d = 7000
⇒ 5000 + (n – 1) × 200 = 7000
⇒ (n – 1) × 200 = 2000
⇒ n – 1 = 2000/200
⇒ n – 1 = 10
⇒ n = 10 + 1 = 11
Thus, 11th salary received by Suba Rao will be Rs 7000. This means that after 10 years i.e. in the year 2005 his annual salary will reach to Rs 7000.