Question

0.45 g of acid of molecular weight 90 was neutralized by 20 ml. of a 0.5N caustic potash. The basicity of an acid is 

(a) 1 

(b) 2 

(c) 3 

(d) 4

Answer 1

Correct option: (b) 2

Explanation:

No. of equivalents of caustic soda = 20 × 10^–3 × 0.5 = 10^–2