Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.3k views
in CBSE by (20 points)
Find the following system of equations grapically 2x-3y+6=0and 2x+3y-18=0 also find the area of the region bounded by there 2 lines and y-axis

Please log in or register to answer this question.

1 Answer

+1 vote
by (1.9k points)

The given system of equations:

2x-3y+6=0 and 2x+3y-18=0

Now,2x-3y+6=0

y= (2x+6)/3

When x=0, then y=2

When x=-3, then y=0

Thus, we have the following table:

X 0 -3
Y 2 6

We have

2x+3y-18=0

X= 18−3y/2

When y=2, then x=6

When y=6, then x=0

Thus, we have the following table:

X 6 0
Y 2 6

Graph of the given system of equations:

38

Clearly, the two lines intersect at A(3,4) .Hence x=3 and y=4 is the solution of the given system of equations.

From the graph, we have

AD=x-coordinate point A(3,4) =3

BC=6-2 = 4

Area of the shaded region = 1/2×base×altitude

= 1/2×4×3

= 6 sq. units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...