Angular fringe separation in water
[If the double slit apparatus is immersed in a liquid of refractive index n, the optical path difference between S2P and S1P of Fig. 12.1 becomes n(S2P – S1P) ≈ (nd x/D ≈ (nd) sin θ. In Eqns. (12.5) and (12.6) d is replaced by (nd) so that the fringe width becomes λD (nd) i.e., the fringes are shrunk].