Match List I with List II and select the correct answer using the code given below the lists :
| List - I |
List - II |
| P. If (0, α) lies inside the triangle formed by the lines y – 3x + 2 = 0, 3y – 2x – 5 = 0 and 4y + x – 14 = 0, then one possible value of [2α], where [ · ] denotes greatest integer function |
1. –2 |
| Q. The point (α2, α + 1) lies in the angle between the lines 3x – y + 1 = 0 & x + 2y – 5 = 0 containing the origin then one possible value of [2α], where [ · ] denotes greatest integer function |
2. –1 |
| R. The centre of circle touching the straight line 3x – y = 2 at (1, 1) & passing through (1, –1) is (a, b) then a – 3b = |
3. 1 |
| S. Locus of a point which is equidistant from (1, 2) & (–2, –1) is ax + by + c = 0 , (a > 0), then a – 2b = |
4. 2 |
|
P |
Q |
R |
S |
| (A) |
4 |
2 |
3 |
1 |
| (B) |
2 |
3 |
1 |
4 |
| (C) |
3 |
1 |
4 |
2 |
| (D) |
1 |
4 |
3 |
2 |
